Ultrasonic testing formulas for UT Level II, worked examples
The UT math is where General exam points are won or lost, and you can learn all of it here. ASNT's NDT Level II examinations page gives the exam size (50 items, 2 hours) and points you to the computer-based testing and calculator demo. The geometry and physics below sit under its topics on techniques, weldments and evaluation.
Check anything you rely on against your own licensed code book and the edition your AHJ enforces.
The equations come from Evident's published UT material, linked at each formula. Where two sources write the same idea differently, both are shown. Every worked example uses made-up numbers for an imaginary probe and test material. For what the exam covers, read the UT Level II General exam guide. For a plain-English page on each term behind these formulas, see the NDT terms glossary.
Every formula below, with the MT current rules and a worked check for each, fits on the printable UT and MT formula sheet (PDF). It follows the UT General topic list for exams prior to 5 February 2027 and the MT General list for exams prior to 15 December 2026. Free, no email.
Units and conventions used on this page
- Velocity in mm/µs (1 mm/µs is 1 km/s, or 1,000 m/s). Frequency in MHz. With those two, wavelength and near field come out in mm with no extra conversion.
- Angles are measured from the normal (a line square to the surface), as on Evident's angle beam diagrams.
- Flat, parallel surfaces and an isotropic material. Curved parts, wedge delay and real beam width are ignored.
- Acoustic impedance in units of 10⁶ kg/(m²·s), the units in Evident's materials table. Density in g/cm³ times velocity in km/s gives the same units.
- Answers are rounded at the end, not between steps.
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Discontinuity Detection
A planar reflector gives its highest echo amplitude when the beam strikes it
Press A-D or 1-4 to choose an answer while this question is on screen.
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Wavelength
λ = c / f (Open in calculator), where c is the sound velocity in the material and f is the frequency. Evident gives this as Equation 2 of its transducer technical notes (p. 2). The velocity must match the wave mode. A shear wave in the same part has a shorter wavelength than a longitudinal wave, because shear velocity is lower.
Worked example. A 4 MHz shear wave travels in a test alloy at 3.10 mm/µs.
λ = 3.10 / 4 = 0.775 mm
Halve the frequency and the wavelength doubles.
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Near field length
Evident's beam characteristics tutorial (section 2.4) gives the near field of a circular element as N = D²f / 4c, or the same thing written as N = D² / 4λ (Open in calculator), where D is the element diameter. The near field ends at the last on-axis maximum. Amplitude-based evaluation is harder inside it, because the sound pressure there swings between maxima and minima.
Two versions in Evident's own material. The technical notes (p. 10) say the near field table was calculated from a fuller expression, N = (D² / 4λ) × [1 − (λ / D)²], and that the short form was derived from it. When D is many wavelengths across, the correction term is tiny. If a practice source gives an answer slightly lower than yours, it may be using the fuller form, so check which one it uses before marking yourself wrong.
Worked example. A 12 mm diameter, 4 MHz element on a material with a longitudinal velocity of 6.00 mm/µs.
- λ = 6.00 / 4 = 1.50 mm
- Short form: N = 12² × 4 / (4 × 6.00) = 576 / 24 = 24.0 mm
- Fuller form: N = (144 / 6.00) × [1 − (1.50 / 12)²] = 24.0 × 0.984 = 23.6 mm
Either way, a reflector at 10 mm depth sits inside the near field. Three more probe comparisons are in near field, beam spread and dead zone: how they differ in UT.
Beam spread
Evident's flaw detection tutorial PDF (section 2.5, p. 16) gives the −6 dB half-angle of an unfocused transducer as sin(α) = 0.514 c / (f D) (Open in calculator). The technical notes (Equation 11, p. 5) write the same relation as sin(α/2) and define α/2 as the half-angle between the −6 dB points, so both describe the angle from the beam axis to the −6 dB edge. Beam spread shrinks as frequency or element diameter goes up.
The constant depends on where you call the edge of the beam. TWI's FAQ on beam spread in the far zone uses a constant of 1.08 for the edge where energy is down to one tenth (−20 dB), and 1.22 for the extreme edge of the beam. A larger constant gives a wider angle for the same probe. Use the constant your question or procedure names, and never mix two conventions in one answer.
Worked example. The same 12 mm, 4 MHz probe on the 6.00 mm/µs material, using Evident's −6 dB constant.
sin(α) = 0.514 × 6.00 / (4 × 12) = 3.084 / 48 = 0.0643
α = 3.7° from the beam axis to the −6 dB edge
Check your own numbers with the UT beam calculator, which shows the constant and dB edge it used.
Snell's law and the critical angles
Snell's law links the sines of the angles to the velocities on each side of the boundary. Evident writes it as sin θi / ci = sin θrl / crl = sin θrs / crs (Open in calculator), with θi the incident angle in the wedge, θrl and θrs the refracted longitudinal and shear angles, and c the matching velocities (technical notes, Equation 12, p. 6; wave front tutorial, section 2.5).
The two critical angles follow from setting a refracted angle to 90° (Open in calculator):
- First critical angle: the incident angle that refracts the longitudinal wave to 90°. Beyond it, only a shear wave enters the part. sin θ₁ = c(wedge) / c(longitudinal in part).
- Second critical angle: the incident angle that refracts the shear wave to 90°, where Evident says a surface wave forms. sin θ₂ = c(wedge) / c(shear in part).
A critical angle only exists when the second material is faster than the wedge for that wave mode.
Worked example. A plastic wedge with a longitudinal velocity of 2.60 mm/µs on a test alloy with longitudinal 6.00 mm/µs and shear 3.10 mm/µs. What wedge angle gives a 60° shear wave, and where are the critical angles?
- sin θi = (2.60 / 3.10) × sin 60° = 0.8387 × 0.8660 = 0.7264, so θi = 46.6°
- First critical: sin θ₁ = 2.60 / 6.00 = 0.4333, so θ₁ = 25.7°
- Second critical: sin θ₂ = 2.60 / 3.10 = 0.8387, so θ₂ = 57.0°
46.6° sits between the two critical angles, so only the shear wave enters the alloy. Check your own numbers with the Snell's law calculator. Five more cases, including both critical angles, are in Snell's law in UT: worked examples and critical angles.
Skip distance, sound path, surface distance and depth
Evident's angle beam inspection section (section 5.2, p. 36) and the technical notes (p. 7) give the flat-plate geometry, with T the thickness and θ the refracted angle (Open in calculator):
- Leg (sound path to the back wall) = T / cos θ
- V path (full skip sound path) = 2T / cos θ
- Skip distance = 2T × tan θ (half skip is T × tan θ)
- Surface distance = sound path × sin θ
- Depth, first leg = sound path × cos θ
- Depth, second leg = 2T − (sound path × cos θ)
Skip distance is measured on the surface from the beam index point. Sound path here is the one-way path in the part, not the wedge.
Worked example. A 20 mm plate scanned with a 60° probe. An indication peaks at a sound path of 55 mm.
- Leg = 20 / cos 60° = 40.0 mm, so V path = 80.0 mm
- Skip distance = 2 × 20 × tan 60° = 69.3 mm (half skip 34.6 mm)
- 55 mm is longer than one leg, so the reflector is on the second leg
- Surface distance = 55 × sin 60° = 47.6 mm from the beam index point
- Depth = 40 − (55 × cos 60°) = 40 − 27.5 = 12.5 mm
A common slip is to use the first-leg depth formula on a second-leg signal, which here would give 27.5 mm, deeper than the plate. If depth comes out larger than T, recheck the leg. The skip distance calculator works the same geometry for legs 1 and 2. For a straight pulse-echo thickness from transit time, the ultrasonic thickness calculator works T = V × t ÷ 2 with a zero offset.
Decibel and amplitude ratio
Evident defines the decibel difference between two amplitudes as dB = 20 log₁₀ (amplitude ratio) (Open in calculator). Its documents put the ratio different ways round. The tutorial glossary (p. 72) uses 20 log (V2 / V1), while the technical notes (Equation 5, p. 3) use 20 log (A1 / A2). The size of the answer is the same; only the sign changes. Our decibel calculator reports a positive number when the second signal is higher than the first.
Going the other way, ratio = 10^(dB / 20) (Open in calculator). Each 6 dB is close to a doubling of amplitude, and 20 dB is a factor of 10.
Worked example. A reference echo is set to 80% full screen height. A second echo reads 32%, with the gain unchanged.
- dB = 20 log₁₀ (32 / 80) = 20 log₁₀ (0.4) = −8.0 dB
- To bring the second echo up to the reference height, add about 8.0 dB of gain.
- Reverse check: a 9 dB difference is an amplitude ratio of 10^(9/20) = 2.82
These calculations assume the screen reading is linear and not clipped above 100%. The shortcuts and four more examples are in decibels in ultrasonic testing: the 6 dB and 20 dB rules.
Acoustic impedance and reflection coefficient
Acoustic impedance is Z = ρc, density times velocity (technical notes, Equation 6, p. 4; Open in calculator). When sound meets a boundary square to the beam, the impedance mismatch decides how much is reflected. Evident's tutorial (section 2.5, p. 17) states that similar impedances reflect little, identical ones reflect nothing in theory, and a very large mismatch such as steel to air reflects close to 100%.
Amplitude versus energy. The tutorial gives R = (Z₂ − Z₁) / (Z₂ + Z₁) and labels R a percentage of sound energy. The technical notes (Equations 7a and 7b, p. 4) square the impedance terms when they work out energy loss: reflected energy uses (Z₂ − Z₁)² / (Z₁ + Z₂)², and transmitted energy uses 4Z₁Z₂ / (Z₁ + Z₂)². The unsquared ratio is the sound pressure (amplitude) ratio and the squared form is the energy fraction. The two energy fractions add up to 1, which is a quick check. Read the question carefully for which one it wants.
Worked example. Sound in a solid with density 7.0 g/cm³ and velocity 5.0 mm/µs meets a liquid with density 1.2 g/cm³ and velocity 1.6 mm/µs.
- Z₁ = 7.0 × 5.0 = 35.0; Z₂ = 1.2 × 1.6 = 1.92 (both × 10⁶ kg/(m²·s))
- Amplitude ratio = (1.92 − 35.0) / (1.92 + 35.0) = −33.08 / 36.92 = −0.896. The minus sign means the echo is phase inverted, which Evident notes happens when Z₂ is lower than Z₁.
- Reflected energy = 0.896² = 0.803, about 80%
- Transmitted energy = 4 × 35.0 × 1.92 / 36.92² = 0.197, about 20%
- Check: 0.803 + 0.197 = 1.000
Magnetizing current for MT
MT candidates meet a separate set of current rules. ASNT's MT General topic list for exams prior to 15 December 2026 includes "Magnetization by Means of Electric Current", and the list for exams after that date names coil, prod and direct contact techniques (examinations page). Portland Community College's WLD 204 Magnetic Testing packet (printed pp. 9 and 10), written for an NSF ATE project, gives these study rules:
- Coil shot: ampere-turns AT = 45,000 / (L/D) (Open in calculator), where L is the part length and D its diameter. Divide by the number of coil turns to get amperes. The packet asks for an L/D of 3 or greater.
- Prods: 90 to 110 A per inch of prod spacing for stock less than 3/4 in thick, and 100 to 125 A per inch for thicker parts (Open in calculator). Keep prod spacing from 3 to 8 in.
Worked example. A made-up part 10 in long and 2 in across sits in a 5-turn coil, and a weld on 1/2 in plate is checked with prods 6 in apart.
- L/D = 10 / 2 = 5, so AT = 45,000 / 5 = 9,000 ampere-turns
- Coil current = 9,000 / 5 = 1,800 A
- Prod current = 6 × 90 to 6 × 110 = 540 to 660 A
Other sources give a second coil formula for a part that fills the coil, and different direct contact (head shot) rates. The MT amperage calculator shows the rules it applies and the paragraph numbers they come from. On a real part, your written procedure sets the current.
How to practice these
- Draw the beam path for every angle beam question. A sketch catches the wrong-leg error quickly.
- Work each example by hand, then confirm it with the matching calculator.
- Work reflection and transmission for any two materials in the acoustic impedance calculator. Run fresh numbers through every formula on this page with the NDT math drill, which gives you ten new problems a set and shows the steps.
- When a source gives a different answer, find the convention first: the beam edge constant, the near field form, the dB ratio direction, or amplitude versus energy.
If your exam is after 5 February 2027, read the UT outline change guide as well.
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Sources
Show the list
- ASNT NDT Level II Examinations, ASNT Certification Services.
- Ultrasonic Flaw Detection Tutorial (PDF, 2021), Olympus, hosted by Evident: sections 2.4, 2.5 and 5.2, glossary p. 72.
- Ultrasonic Transducers Technical Notes (PDF, 2019), Olympus, hosted by Evident: Equations 2, 5, 6, 7a, 7b, 8, 8a, 11 and 12, and pp. 7 and 10.
- WLD 204 Non Destructive Testing I: Magnetic Testing (PDF), Portland Community College Welding Technology (NSF ATE project): printed pp. 9 and 10.
Facts come from the sources listed above. If something has changed, tell us and we will correct it within 2 business days.
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